Difference between revisions of "Quotients (Topology)"

From Queer Beagle Wiki
 
(One intermediate revision by the same user not shown)
Line 16: Line 16:
 
# If $$f$$ also satisfies the property that whenever $$x,x' ∈ X $$ and $$f(x) = f(x')$$ then $$x ∼ x'$$, then $$g$$ is one-to-one.
 
# If $$f$$ also satisfies the property that whenever $$x,x' ∈ X $$ and $$f(x) = f(x')$$ then $$x ∼ x'$$, then $$g$$ is one-to-one.
  
 +
<!-- Let $$X$$ be a topological space and let $$∼$$ be an equivalence relation on $$X$$. Let $$X/∼$$ be the set of equivalence classes and let $$q: X → X/∼$$ be the equivalence map (defined by $$q(p) := [p]$$ for all $$p$$ in $$X$$). -->
  
(<!-- Let $$X$$ be a topological space and let $$∼$$ be an equivalence relation on $$X$$. Let $$X/∼$$ be the set of equivalence classes and let $$q: X → X/∼$$ be the equivalence map (defined by $$q(p) := [p]$$ for all $$p$$ in $$X$$). -->) The '''quotient topology''', or identification topology on $$X/∼$$ induced by $$∼$$, is the topology $$𝒯∼ = 𝒯_{\rm quo}:= \{U ⊆ X/∼ | q^{-1}(U) \text{ is open in }X\}$$. The set $$X/∼$$ together with the quotient topology is called a '''quotient space of $$X$$''', and the equivalence map $$q$$ is called the '''quotient map''' induced by $$∼$$.
+
The '''quotient topology''', or identification topology on $$X/∼$$ induced by $$∼$$, is the topology $$𝒯∼ = 𝒯_{\rm quo}:= \{U ⊆ X/∼ | q^{-1}(U) \text{ is open in }X\}$$. The set $$X/∼$$ together with the quotient topology is called a '''quotient space of $$X$$''', and the equivalence map $$q$$ is called the '''quotient map''' induced by $$∼$$.
 +
 
 +
[[Category:Point-Set Topology]]

Latest revision as of 21:34, 21 May 2023

The quotient of $$X$$ with respect to $$∼$$, $$X/∼$$ denotes the set of equivalence classes

The function $$q:X → X/∼$$ defined by $$q(p) := [p]$$ for all $$p ∈ X$$ is called the equivalence map.

The equivalence class of an element $$a$$ of $$X$$ is $$[a] := \{b | b ∼ a\}$$.

An equivalence relation $$∼$$ on a set $$X$$ is a subset $$S$$ of $$X × X$$ (where $$(a,b) ∈ S$$ is written $$a ∼ b$$) that satisfies the following for all $$a,b,c \in X$$:

  1. Reflexive: $$a ∼ a$$
  2. Symmetric: $$a ∼ b$$ implies $$b ∼ a$$
  3. Transitive: $$a ∼ b$$ and $$b ∼ c$$ implies $$a ∼ c$$


FBT = Function Building Theorem for quotient sets: Let $$∼$$ be an equivalence relation on a set $$X$$, and let $$f: X → Y$$ be a function satisfying the property that whenever $$x,x' ∈ X$$ and $$x ∼ x'$$ then $$f(x) = f(x')$$. Then:

  1. There is a well-defined function $$g:X/∼ → Y$$ defined by $$g([x]) = f(x)$$ for all in $$X/∼$$; that is, $$g ∘ q = f$$, where $$q$$ is the equivalence map.
  2. If $$f$$ is onto, then $$g$$ is onto.
  3. If $$f$$ also satisfies the property that whenever $$x,x' ∈ X $$ and $$f(x) = f(x')$$ then $$x ∼ x'$$, then $$g$$ is one-to-one.


The quotient topology, or identification topology on $$X/∼$$ induced by $$∼$$, is the topology $$𝒯∼ = 𝒯_{\rm quo}:= \{U ⊆ X/∼ | q^{-1}(U) \text{ is open in }X\}$$. The set $$X/∼$$ together with the quotient topology is called a quotient space of $$X$$, and the equivalence map $$q$$ is called the quotient map induced by $$∼$$.